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5k^2-9k-7=0
a = 5; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·5·(-7)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{221}}{2*5}=\frac{9-\sqrt{221}}{10} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{221}}{2*5}=\frac{9+\sqrt{221}}{10} $
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